If the circuit voltage remains the same and resistance is halved, what happens to power according to P = V^2 / R?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Get ready for the NCCER Introduction to Electrical Circuits exam. Study with multiple choice questions, each question comes with hints and explanations. Ace your exam with confidence!

Multiple Choice

If the circuit voltage remains the same and resistance is halved, what happens to power according to P = V^2 / R?

Explanation:
With the voltage fixed, power varies inversely with resistance. Using P = V^2 / R, halving the resistance makes the denominator half, so the power becomes P' = V^2 / (R/2) = 2V^2 / R = 2P. So the power doubles. This lines up with the idea that current I = V/R doubles when R is halved (for the same V), and since P = VI, the power doubles as well.

With the voltage fixed, power varies inversely with resistance. Using P = V^2 / R, halving the resistance makes the denominator half, so the power becomes P' = V^2 / (R/2) = 2V^2 / R = 2P. So the power doubles. This lines up with the idea that current I = V/R doubles when R is halved (for the same V), and since P = VI, the power doubles as well.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy