What is the power dissipated by the 10 Ω resistor carrying 2 A?

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Multiple Choice

What is the power dissipated by the 10 Ω resistor carrying 2 A?

Explanation:
Power dissipated by a resistor is found from P = I^2 R. With a current of 2 A through a 10 Ω resistor, P = (2)^2 × 10 = 40 W. You can also get it from the voltage: V = I R = 2 × 10 = 20 V, and P = V × I = 20 × 2 = 40 W. So the dissipated power is 40 watts.

Power dissipated by a resistor is found from P = I^2 R. With a current of 2 A through a 10 Ω resistor, P = (2)^2 × 10 = 40 W. You can also get it from the voltage: V = I R = 2 × 10 = 20 V, and P = V × I = 20 × 2 = 40 W. So the dissipated power is 40 watts.

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